5=x^2+2x-30

Solution for 5=x^2+2x-30 equation:

5=x^2+2x-30

We move all terms to the left:

5-(x^2+2x-30)=0

We get rid of parentheses

-x^2-2x+30+5=0

We add all the numbers together, and all the variables

-1x^2-2x+35=0

a = -1; b = -2; c = +35;
Δ = b2-4ac
Δ = -22-4·(-1)·35
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-12}{2*-1}=\frac{-10}{-2}
=+5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+12}{2*-1}=\frac{14}{-2}
=-7
$